A 100 mL solution of CH 3 CH 2 MgBr on treatment with methanol produces 2 . 24 mL of a gas at STP. The weight of gas produced is____mg (nearest integer)

Step-by-step solution

In the above reaction the Ethyl group of grignard reagent acts as a strong base. As per the stoichiometric equation the number of moles of methanol is equal to the number of moles of ethane. Volume of methanol = Volume of ethane = 2 . 24 ml Hence, number of moles of ethane n = 2 . 24 × 10 - 3 22 . 4 = 10 - 4 Weight of the gas= Number of moles × Molecular mass W = n × M = 10 - 4 × 30 = 3 mg