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JEE Main 20188 April
Exam
JEE Main
Year
2018
Date
8 April
Subject
Chemistry
Chapter
Alcohols Phenols and Ethers

JEE Main 2018 · 8 April · Chemistry · Alcohols Phenols and Ethers

Phenol reacts with methyl chloroformate in the presence of NaOH to...

Phenol reacts with methyl chloroformate in the presence of NaOHNaOH to form product A.AA . Areacts with Br2{Br}_{2} to form product B.AandBB . AandB are respectivelyPhenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to formPhenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to formPhenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to formPhenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to formPhenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to formPhenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to form

Options

  1. AUpon the insertion of an iron core with a cross-sectional area of 4 cm^2 , the magnetic field inside a long solenoid
  2. BUpon the insertion of an iron core with a cross-sectional area of 4 cm^2 , the magnetic field inside a long solenoid
  3. CUpon the insertion of an iron core with a cross-sectional area of 4 cm^2 , the magnetic field inside a long solenoid
  4. DUpon the insertion of an iron core with a cross-sectional area of 4 cm^2 , the magnetic field inside a long solenoid

Correct answer

D. Upon the insertion of an iron core with a cross-sectional area of 4 cm^2 , the magnetic field inside a long solenoid

Step-by-step solution

Phenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to form
This step involves acid-base reaction at first followed by nucleophilic addition elimination.
Phenol reacts with methyl chloroformate in the presence of NaOH to form product A . A reacts with Br _ 2 to form
This step is called bromination.
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