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JEE Main 20188 April
Exam
JEE Main
Year
2018
Date
8 April
Subject
Chemistry
Chapter
Alcohols Phenols and Ethers

JEE Main 2018 · 8 April · Chemistry · Alcohols Phenols and Ethers

Phenol on treatment with C O _ 2 in the presence of NaOH followed...

Phenol on treatment with CO2C{O}_{2} in the presence of NaOH followed by acidification produces compound X as the major product. X on treatment with (CH3 CO ){\left(C{H}_{3}\text{ CO }\right)}_{2}OinthepresenceofcatalyticamountofO in the presence of catalytic amount of{H}_{2}S{O}_{4} produces:Phenol on treatment with C O _ 2 in the presence of NaOH followed by acidification produces compound X as the majorPhenol on treatment with C O _ 2 in the presence of NaOH followed by acidification produces compound X as the majorPhenol on treatment with C O _ 2 in the presence of NaOH followed by acidification produces compound X as the majorPhenol on treatment with C O _ 2 in the presence of NaOH followed by acidification produces compound X as the majorPhenol on treatment with C O _ 2 in the presence of NaOH followed by acidification produces compound X as the major

Options

  1. AA galvanometer of resistance 25Ω is connected to a battery of 2V along with a resistance of 3000Ω . In this case, a
  2. BA galvanometer of resistance 25Ω is connected to a battery of 2V along with a resistance of 3000Ω . In this case, a
  3. CA galvanometer of resistance 25Ω is connected to a battery of 2V along with a resistance of 3000Ω . In this case, a
  4. DA galvanometer of resistance 25Ω is connected to a battery of 2V along with a resistance of 3000Ω . In this case, a

Correct answer

B. A galvanometer of resistance 25Ω is connected to a battery of 2V along with a resistance of 3000Ω . In this case, a

Step-by-step solution

Two different reactions are taking place here Kolbe–Schmitt reaction and esterification reaction (treatment of the product of Kolbe–Schmitt reaction with (CH3CO)2O(ester).{( {CH}_{3}CO )}_{2}O ( ester ) .

The two reactions can be written as follows:

1.Kolbe–Schmitt reaction: reaction of phenol with carbon dioxide in the presence of sodium hydroxide, followed by acidification converts phenol to 1−1− hydroxybenzoic acid (Salicylic acid).

2.Esterification reaction: The salicylic acid is then reacted with acetic anhydride (CH3CO)2O){( {CH}_{3}CO )}_{2}O )to form aspirin.

Phenol on treatment with C O _ 2 in the presence of NaOH followed by acidification produces compound X as the major

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