JEE Main202330 Jan 2023Morning ShiftChemistryCarboxylic Acid DerivativesActual
A trisubstituted compound ' A ', C 10 H 12 O 2 gives neutral FeCl 3 test positive. Treatment of compound ' A ' with NaOH and CH 3 Br gives C 11 H 14 O 2 , with hydroiodic acid gives methyl iodide and with hot conc. NaOH gives a compound B , C 10 H 12 O 2 . Compound ' A ' also decolorises alkaline KMnO 4 . The number of π bond/s present in the compound ' A ' is _____ .
Correct answer
0
Step-by-step solution
The trisubstituted compound ' A ', C 10 H 12 O 2 gives neutral FeCl 3 test positive, means the compound is phenol. Phenol on treatment with NaOH and CH 3 Br gives C 10 H 11 O 2 CH 3 . The given compound is reacting with hot conc. NaOH gives a compound B , C 10 H 12 O 2 . The reaction is Cannizzaro's reaction. Hence, compound must be benzaldehyde derivative. Compound ' A ' also decolourises alkaline KMnO 4 , means compound contains an alkyl group attached to benzene ring. Hence, the structure of