JEE Main 20199 JanuaryMorning Shift

Exam: JEE Main
Year: 2019
Date: 9 January
Shift: Morning Shift
Subject: Chemistry
Chapter: Carboxylic Acid Derivatives

JEE Main 2019 · 9 January · Morning Shift · Chemistry · Carboxylic Acid Derivatives

Acid strength given below the correct decreasing order will be :

Options

A ${NO}_{2}{CH}_{2}COOH > {FCH}_{2}COOH > {CNCH}_{2}COOH > {ClCH}_{2}COOH$
B ${NO}_{2}{CH}_{2}COOH > {NCCH}_{2}COOH > {FCH}_{2}COOH > {ClCH}_{2}COOH$
C ${CNCH}_{2}COOH > {O}_{2}{NCH}_{2}COOH > {FCH}_{2}COOH > {ClCH}_{2}COOH$
D ${FCH}_{2}COOH > {NCCH}_{2}COOH > {NO}_{2}{CH}_{2}COOH > {ClCH}_{2}COOH$

Correct answer

B. ${NO}_{2}{CH}_{2}COOH > {NCCH}_{2}COOH > {FCH}_{2}COOH > {ClCH}_{2}COOH$

Step-by-step solution

Acidic character $\alpha$ stability of conjugate base (anion)

Stability of anion $\alpha – I$

Hence greater the $– I$ effect greater will be the acidity

Order of -I-effect $- {NO}_{2} > CN > - F > - Cl$ Hence, order of acidity will be

$\begin{array}{ll}{O}_{2}{NCH}_{2}COOH > NC{CH}_{2}COOH > {FCH}_{2}COOH > Cl{CH}_{2}COOH\end{array}$

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