JEE Main 202622 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Chemical Bonding and Molecular Structure
JEE Main 2026 · 22 January · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure
Two p-block elements X and Y form fluorides of the type EF_ 3 . The...
Two p-block elements X and Y form fluorides of the type . The fluoride compound is a Lewis acid and is a Lewis base. The hybridizations of the central atoms of and respectively are
Options
- A and
- BBoth
- C and
- DBoth
Correct answer
A. and
Step-by-step solution
XF₃ is a Lewis acid, indicating the central atom X lacks a complete octet and can accept electron pairs. This is characteristic of Boron (B).
Boron in BF₃:
Valence electrons: 3
Steric number: 3 (three B-F bonds, no lone pairs)
Geometry: Trigonal planar
Hybridization: sp²
YF₃ is a Lewis base, indicating the central atom Y has lone pair(s) available to donate. This is characteristic of Nitrogen (N).
Nitrogen in NF₃:
Valence electrons: 5
Steric number: 4 (three N-F bonds + one lone pair)
Geometry: Trigonal pyramidal
Hybridization: sp³
Therefore, the hybridizations are sp² for XF₃ (Boron) and sp³ for YF₃ (Nitrogen).
Boron in BF₃:
Valence electrons: 3
Steric number: 3 (three B-F bonds, no lone pairs)
Geometry: Trigonal planar
Hybridization: sp²
YF₃ is a Lewis base, indicating the central atom Y has lone pair(s) available to donate. This is characteristic of Nitrogen (N).
Nitrogen in NF₃:
Valence electrons: 5
Steric number: 4 (three N-F bonds + one lone pair)
Geometry: Trigonal pyramidal
Hybridization: sp³
Therefore, the hybridizations are sp² for XF₃ (Boron) and sp³ for YF₃ (Nitrogen).