JEE Main202622 January 2026Morning ShiftChemistryChemical Bonding and Molecular StructureActual
The formal charges on the atoms marked as (1) to (4) in the Lewis representation of HNO ₃ molecule respectively are
Options
- A0,0,-1,+1
- B0,-1,0,+1
- C+1,0,0,-1
- D0,+1,0,-1
Correct answer
D. 0,+1,0,-1
Step-by-step solution
The formal charge (F.C.) of an atom in a Lewis structure is calculated using the formula: F.C. = [Total valence electrons] - [Total non-bonding (lone pair) electrons] - 1 2 [Total bonding (shared) electrons] For atom (1) Oxygen: Valence e^- = 6 , Lone pair e^- = 4 , Bonding e^- = 4 . F.C. = 6 - 4 - 1 2 (4) = 0 For atom (2) Nitrogen: Valence e^- = 5 , Lone pair e^- = 0 , Bonding e^- = 8 . F.C. = 5 - 0 - 1 2 (8) = +1 For atom (3) Oxygen: Valence e^- = 6 , Lone pair e^- = 4 , Bonding e^- = 4 . F.C. = 6 - 4 - 1 2 (4) =