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JEE Main 202523 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
23 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Main 2025 · 23 January · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure

Match the LIST-I with LIST-II Choose the correct answer from the...

Match the LIST-I with LIST-II Match the LIST-I with LIST-II Choose the correct answer from the options given below:
Choose the correct answer from the options given below:

Options

  1. AA-IV, B-I, C-III, D-II
  2. BA-IV, B-II, C-I, D-III
  3. CA-II, B-IV, C-III, D-I
  4. DA-III, B-II, C-I, D-IV

Correct answer

B. A-IV, B-II, C-I, D-III

Step-by-step solution

NO=7e−\mathrm{NO}=7 \mathrm{e}^{-}Incomplete octet with NO2=7e−∫\mathrm{NO}_2=7 \mathrm{e}^{-} \int \quad odd electron BCl3=6e−AlCl3=6e−\begin{array}{l}\mathrm{BCl}_3=6 \mathrm{e}^{-} \\ \mathrm{AlCl}_3=6 \mathrm{e}^{-}\end{array}Incomplete octet H2SO4=12e−,PCl5=10e−⇒\mathrm{H}_2 \mathrm{SO}_4=12 \mathrm{e}^{-}, \mathrm{PCl}_5=10 \mathrm{e}^{-} \Rightarrow molecules with expanded octet CCl4=8e−,CO2=8e−⇒\mathrm{CCl}_4=8 \mathrm{e}^{-}, \mathrm{CO}_2=8 \mathrm{e}^{-} \Rightarrow molecules obeying octet rule
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