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JEE Main 202522 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Main 2025 · 22 January · Evening Shift · Chemistry · Chemical Bonding and Molecular Structure

Arrange the following compounds in increasing order of their dipole...

Arrange the following compounds in increasing order of their dipole moment : HBr,H2 S,NF3\mathrm{HBr}, \mathrm{H}_2 \mathrm{~S}, \mathrm{NF}_3 and CHCl3\mathrm{CHCl}_3

Options

  1. AH2 S<HBr<NF3<CHCl3\mathrm{H}_2 \mathrm{~S} \lt \mathrm{HBr} \lt \mathrm{NF}_3 \lt \mathrm{CHCl}_3
  2. BNF3<HBr<H2 S<CHCl3\mathrm{NF}_3 \lt \mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S} \lt \mathrm{CHCl}_3
  3. CHBr<H2 S<NF3<CHCl3\mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S} \lt \mathrm{NF}_3 \lt \mathrm{CHCl}_3
  4. DCHCl3<NF3<HBr<H2 S\mathrm{CHCl}_3 \lt \mathrm{NF}_3 \lt \mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S}

Correct answer

B. NF3<HBr<H2 S<CHCl3\mathrm{NF}_3 \lt \mathrm{HBr} \lt \mathrm{H}_2 \mathrm{~S} \lt \mathrm{CHCl}_3

Step-by-step solution

μHBr=0.78DμH2 S=0.95DμNF3=0.24DμCHCl3=1.01D\begin{aligned} & \mu_{\mathrm{HBr}}=0.78 \mathrm{D} \\ & \mu_{\mathrm{H}_2 \mathrm{~S}}=0.95 \mathrm{D} \\ & \mu_{\mathrm{NF}_3}=0.24 \mathrm{D} \\ & \mu_{\mathrm{CHCl}_3}=1.01 \mathrm{D} \end{aligned} Hence dipole moment of NF3<HBr<H2 S<CHCl3\mathrm{NF}_3 < \mathrm{HBr} < \mathrm{H}_2 \mathrm{~S} < \mathrm{CHCl}_3
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