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JEE Main 20241 FebruaryMorning Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Main 2024 · 1 February · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure

Arrange the bonds in order of increasing ionic character in the...

Arrange the bonds in order of increasing ionic character in the molecules. LiF,K2O,N2,SO2LiF, {K}_{2}O, {N}_{2}, {SO}_{2} and ClF3.{ClF}_{3} .

Options

  1. AClF3<N2<SO2<K2O<LiF{ClF}_{3} < {N}_{2} < {SO}_{2} < {K}_{2}O < LiF
  2. BLiF<K2O<ClF3<SO2<N2LiF < {K}_{2}O < {ClF}_{3} < {SO}_{2} < {N}_{2}
  3. CN2<SO2<ClF3<K2O<LiF{N}_{2} < {SO}_{2} < {ClF}_{3} < {K}_{2}O < LiF
  4. DN2<ClF3<SO2<K2O<LiF{N}_{2} < {ClF}_{3} < {SO}_{2} < {K}_{2}O < LiF

Correct answer

C. N2<SO2<ClF3<K2O<LiF{N}_{2} < {SO}_{2} < {ClF}_{3} < {K}_{2}O < LiF

Step-by-step solution

The ionic character in a molecule is dependent upon the electronegativity difference between the constituting atoms. The greater the difference, the greater will be the ionic character of the molecule.

N2<SO2<ClF3<K2O<LiF{N}_{2} < {SO}_{2} < {ClF}_{3} < {K}_{2}O < LiF

The Ionic character depends upon the difference in electronegativity (bond polarity).

N2{N}_{2} is a covalent molecule & the difference in electrongegativities are:
|XS – X0| = 1.01 . 0
|XCl – XF| =1.0= 1 . 0
|XK – X0| =2.6= 2 . 6
|XLi – XF| =3.5= 3 . 5

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