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JEE Main20241 Feb 2024Morning ShiftChemistryChemical Bonding and Molecular StructureActual

Arrange the bonds in order of increasing ionic character in the molecules. LiF , K 2 O , N 2 , SO 2 and ClF 3 .

Options

  1. AClF 3 < N 2 < SO 2 < K 2 O < LiF
  2. BLiF < K 2 O < ClF 3 < SO 2 < N 2
  3. CN 2 < SO 2 < ClF 3 < K 2 O < LiF
  4. DN 2 < ClF 3 < SO 2 < K 2 O < LiF

Correct answer

C. N 2 < SO 2 < ClF 3 < K 2 O < LiF

Step-by-step solution

The ionic character in a molecule is dependent upon the electronegativity difference between the constituting atoms. The greater the difference, the greater will be the ionic character of the molecule. N 2 < SO 2 < ClF 3 < K 2 O < LiF The Ionic character depends upon the difference in electronegativity (bond polarity). N 2 is a covalent molecule & the difference in electrongegativities are: |X S – X 0 | = 1 . 0 |X Cl – X F | = 1 . 0 |X K – X 0 | = 2 . 6 |X Li – X F | = 3 . 5

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