The number of molecules/ion/s having trigonal bipyramidal shape is …….. .
${PF}_{5}, {BrF}_{5}, {PCl}_{5}, {\left[{PtCl}_{4}\right]}^{2 -}, {BF}_{3}, Fe ( CO{)}_{5}$

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The number of molecules/ion/s having trigonal bipyramidal shape is …….. . PF _ 5 , BrF _ 5 , PCl _ 5 , [ PtCl _ 4 ] ^ 2 - , BF _ 3 , Fe ( CO ) _ 5

Quantrex Academy · Accepted Answer

Correct answer: 3

PF _ 5 involves sp 3 d hybridisation and hence has trigonal bipyramidal structure. In PCl _ 5 the central atom is surrounded by five bond pairs and no lone paris. Hybridisation of central atom in PCl _ 5 molecule is sp 3 d giving trigonal bipyramidal shape. In [Fe ( CO ) _ 5 ] , oxidation state of CO is zero. It has hybridisation =dsp 3 . So it has trigonal bipyramidal geometry. BrF _ 5 ; square pyramidal [ PtCl _ 4 ] ^ - 2 ; square planar BF _ 3 ; Trigonal planar. Hence the answer is 3

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