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JEE Main202430 Jan 2024Morning ShiftChemistryChemical Bonding and Molecular StructureActual

Match List - I with List-II List I (Molecule) List II (Shape) A. BrF 5 i. T-shape B. H 2 O ii. See saw C. ClF 3 iii. Bent D. SF 4 iv. Square pyramidal

Options

  1. A(A)-I, (B)-II, (C)-IV, (D)-III
  2. B(A) -II, (B)-I, (C)-III, (D)-IV
  3. C(A)-III, (B)-IV, (C)-I, (D)-II
  4. D(A)-IV, (B)-III, (C)-I, (D)-II

Correct answer

D. (A)-IV, (B)-III, (C)-I, (D)-II

Step-by-step solution

(A) The steric number of the central Bromine atom is = 5 bond pairs + one lone pair = 6 . Hence the shape is square pyramidal structure and the hybridisation is sp 3 d 2 . (B) H 2 O molecular geometry is bent because it has two bound atoms and two lone pairs on oxygen, the central atom. The two lone pairs on the oxygen atom push the two hydrogen atoms down further away from the oxygen atom and closer to each other, creating a bent shape and 104 . 5 degrees angle between the two H atoms. (C) The molecular geometry o

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