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JEE Main 202228 JulyMorning Shift
Exam
JEE Main
Year
2022
Date
28 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Main 2022 · 28 July · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure

The number of paramagnetic species among the following is B _ 2 ,...

The number of paramagnetic species among the following is B2,Li2,C2,C2−,O22−,O2+{B}_{2}, {Li}_{2}, {C}_{2}, {C}_{2}^{-}, {O}_{2}^{2 -}, {O}_{2}^{+} and He2+{He}_{2}^{+}

Correct answer

4

Step-by-step solution

The species that contain unpaired electrons are paramagnetic.

Electronic configuration of Li2{Li}_{2} molecule is (σ1s)2(σ∗1s)2(σ2s)2{\left(\sigma1s\right)}^{2}{\left({\sigma}^{*}1s\right)}^{2}{\left(\sigma2s\right)}^{2}.

The electronic configuration of B2{B}_{2} molecule is

(σ1s)2(σ⋆1s)2(σ2s)2(σ⋆2s)2(π2px1=π2py1){\left(\sigma1s\right)}^{2}{\left({\sigma}^{⋆}1s\right)}^{2}{\left(\sigma2s\right)}^{2}{\left({\sigma}^{⋆}2s\right)}^{2}\left(\pi2{{p}_{x}}^{1} = \pi2{{p}_{y}}^{1}\right)

The presence of unpaired electrons in the two π\pi bonding molecular orbitals explains its paramagnetic nature.

The electronic configuration of C2{C}_{2} KKσ2s2σ∗2s2π2px2π2py2KK\sigma2{s}^{2}{\sigma}^{*}2{s}^{2}\pi2{p}_{x}^{2}\pi2{p}_{y}^{2}

O2:KK(σ2s)2(σ2s)2(σ2pz)2(π2px)2=(π2py)2(π∗2px)1=(π∗2py)1{O}_{2}: KK{\left({\sigma}_{2s}\right)}^{2}{\left({\sigma}_{2s}\right)}^{2}{\left({\sigma}_{2{p}_{z}}\right)}^{2}{\left({\pi}_{2{p}_{x}}\right)}^{2} = {\left({\pi}_{2{p}_{y}}\right)}^{2}{\left(\pi{*}_{2{p}_{x}}\right)}^{1} = {\left(\pi{*}_{2{p}_{y}}\right)}^{1}

Hence, O2{O}_{2} molecule is paramagnetic.

The electronic configuration of C2−{C}_{2}^{-} is (σ1s)2(σ⋆1s)2(σ2s)2(σ⋆2s)2(π2px2=π2py2)σ2pz1{\left(\sigma1s\right)}^{2}{\left({\sigma}^{⋆}1s\right)}^{2}{\left(\sigma2s\right)}^{2}{\left({\sigma}^{⋆}2s\right)}^{2}\left(\pi2{{p}_{x}}^{2} = \pi2{{p}_{y}}^{2}\right)\sigma2{{p}_{z}}^{1}

Hence, it is paramagnetic substance.

O22−:KK(σ2s)2(σ2s)2(σ2pz)2(π2px)2=(π2py)2(π∗2px)2=(π∗2py)2{O}_{2}^{2 -}: KK{\left({\sigma}_{2s}\right)}^{2}{\left({\sigma}_{2s}\right)}^{2}{\left({\sigma}_{2{p}_{z}}\right)}^{2}{\left({\pi}_{2{p}_{x}}\right)}^{2} = {\left({\pi}_{2{p}_{y}}\right)}^{2}{\left(\pi{*}_{2{p}_{x}}\right)}^{2} = {\left(\pi{*}_{2{p}_{y}}\right)}^{2}

O2+:KK(σ2s)2(σ2s)2(σ2pz)2(π2px)2=(π2py)2(π∗2px)1=(π∗2py){O}_{2}^{+}: KK{\left({\sigma}_{2s}\right)}^{2}{\left({\sigma}_{2s}\right)}^{2}{\left({\sigma}_{2{p}_{z}}\right)}^{2}{\left({\pi}_{2{p}_{x}}\right)}^{2} = {\left({\pi}_{2{p}_{y}}\right)}^{2}{\left(\pi{*}_{2{p}_{x}}\right)}^{1} = \left(\pi{*}_{2{p}_{y}}\right)

Hence, the above species is paramagnetic.

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