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JEE Main202225 Jul 2022Evening ShiftChemistryChemical Bonding and Molecular StructureActual

Match List I with List II List-I List-II A XeO 3 I sp 3 d ; linear B XeF 2 II sp 3 ; pyramidal C XeOF 4 III sp 3 d 3 ; distorted octahedral D XeF 6 IV sp 3 d 2 ; square pyramidal Choose the correct answer from the options given below

Options

  1. AA - II , B - IV , C - III , D - I
  2. BA - IV , B - II , C - III , D - I
  3. CA - II , B - I , C - IV , D - III
  4. DA - IV , B - II , C - I , D - III

Correct answer

C. A - II , B - I , C - IV , D - III

Step-by-step solution

XeOF 4 S . N = 1 2 8 + 4 = 6 = sp 3 d 2 square pyramidal XeO 3 1 2 8 = 4 = sp 3 Pyramidal XeF 6 1 2 8 + 6 = 7 = sp 3 d 3 distorted octahedral XeF 2 1 2 8 + 2 = 5 = sp 3 d linear

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