The sum of number of lone pairs of electrons present on the central atoms of XeO 3 , XeOF 4 and XeF 6 is

Step-by-step solution

Number of lone pairs on the central atom=Number of hybrid orbitals of the central atom - Number of sigma bonds of the central atom. Number of hybrid orbitals or Hybridisation for a molecule is given by   =   1 2 V + H - C + A Where V= Number of valance electrons in central atom. H = Number of surrounding monovalent atoms. C= Cationic charge A = Anionic charge. XeF 6 :   Number of hybrid orbitals are 7. Number of sigma bonds formed by the central atom are 6 Number of lone pairs on the central atom=7-6