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JEE Main202228 Jun 2022Morning ShiftChemistryChemical Bonding and Molecular StructureActual

The hybridization of P exhibited in PF 5 is sp x d y . The value of y is

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The hybridization is sp 3 d hybridization and phosphorous atom forms five sp 3 d hybrid orbitals. Five hybrid orbitals will be used to form bonds with five fluorine atoms. There are 5 sigma bonds in this compound. PF 5 ⇒ sp 3 d hybridisation ( 5 sigma bonds, zero lone pair on central atom) Value of y = 1

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