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JEE Main 202228 JuneMorning Shift

Exam: JEE Main
Year: 2022
Date: 28 June
Shift: Morning Shift
Subject: Chemistry
Chapter: Chemical Bonding and Molecular Structure

JEE Main 2022 · 28 June · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure

The hybridization of P exhibited in PF _ 5 is sp ^ x d ^ y . The...

The hybridization of

P

exhibited in

{PF}_{5}

is

{sp}^{x}{d}^{y}

. The value of

y

is

Correct answer

0

Step-by-step solution

The hybridization is

{sp}^{3}d

hybridization and phosphorous atom forms five

{sp}^{3}d

hybrid orbitals. Five hybrid orbitals will be used to form bonds with five fluorine atoms. There are

5

sigma bonds in this compound.

${PF}_{5} ⇒ {sp}^{3}d$ hybridisation

( $5$ sigma bonds, zero lone pair on central atom) Value of $y = 1$

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