Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202628 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2026 · 28 January · Evening Shift · Chemistry · Chemical Kinetics

A B (first reaction) C D (second reaction) Consider the above two...

A⟶B\mathrm{A} \longrightarrow \mathrm{B} (first reaction)
C⟶D\mathrm{C} \longrightarrow \mathrm{D} (second reaction)
Consider the above two first-order reactions. The rate constant for first reaction at 500 K is double of the same at 300 K. At 500 K,50%500 \mathrm{~K}, 50 \% of the reaction becomes complete in 2 hour. The activation energy of the second reaction is half of that of first reaction. If the rate constant at 500 K of the second reaction becomes double of the rate constant of first reaction at the same temperature; then rate constant for the second reaction at 300 K is ____\_\_\_\_ ×10−1\times 10^{-1} hour −1^{-1} (nearest integer).

Correct answer

0

Step-by-step solution

For A→K1BA \xrightarrow{K_1} B
ln⁡(2)=Ea1R[1300−1500]\ln(2) = \dfrac{E_{a_1}}{R} \left[ \dfrac{1}{300} - \dfrac{1}{500} \right]
Ea1=ln⁡2×R×15002E_{a_1} = \dfrac{\ln 2 \times R \times 1500}{2}
Ea2=Ea12=ln⁡2×R×15004E_{a_2} = \dfrac{E_{a_1}}{2} = \dfrac{\ln 2 \times R \times 1500}{4}
(K1)at 500 K=ln⁡22(K_1)_{\text{at 500 K}} = \dfrac{\ln 2}{2}
(K2)at 500 K=ln⁡2(K_2)_{\text{at 500 K}} = \ln 2
Now for C→K2DC \xrightarrow{K_2} D
ln⁡[(K2)at 500K(K2)at 300K]=(ln⁡2×R×15004)×1R×[1300−1500]\ln \left[ \dfrac{(K_2)_{\text{at 500K}}}{(K_2)_{\text{at 300K}}} \right] = \left( \dfrac{\ln 2 \times R \times 1500}{4} \right) \times \dfrac{1}{R} \times \left[ \dfrac{1}{300} - \dfrac{1}{500} \right]
(K2)at 300 K=ln⁡22=0.49(K_2)_{\text{at 300 K}} = \dfrac{\ln 2}{\sqrt{2}} = 0.49
(K2)at 300 K=4.9×10−1(K_2)_{\text{at 300 K}} = 4.9 \times 10^{-1}.
So, answer is 5.
Practice Chemical Kinetics on Quantrex Academy →

More from Chemical Kinetics

For a reversible reaction R leftharpoons P , at constant temperature, both the forward… JEE Advanced 2026For a first-order reaction R P at a given temperature, k is the rate constant. For this… JEE Advanced 2026Given below are two statements: R=8.314 J K ^ -1 mol ^ -1 and 1 cal =4.2 J Statement I… JEE Main 2026Decomposition of a hydrocarbon follows the equation k = (5.5 × 10^ 11 \,s^ -1 )\,e^… JEE Main 2026For a reaction A arrow P at T K , the half life (t_ 1/2 ) is plotted as a function of… JEE Main 2026First order gas phase reaction A arrow B + C p_i = initial pressure of gas A, p_t = total… JEE Main 2026If the half life of a first order reaction is 6.93 minutes then the time required for… JEE Main 2026Consider the given graph showing variation of reactant concentration with time. Three… JEE Main 2026 Full Chemical Kinetics list All JEE Main PYQs