Given above is the concentration vs time plot for a dissociation reaction : A arrow nB . Based on the data of the initial phase of the reaction (initial 10 min), the value of n is \_\_\_\_ .

Correct answer: A. 3 A arrow nB At t = 0 : [A] = 0.05 M, [B] = 0 At t = 10 min: [A] = 0.04 M, [B] = 0.01 × n From the graph, [B] at t = 10 min = 0.03 M 0.01 × n = 0.03 n = 3

JEE Main 202623 JanuaryEvening Shift

Exam: JEE Main
Year: 2026
Date: 23 January
Shift: Evening Shift
Subject: Chemistry
Chapter: Chemical Kinetics

JEE Main 2026 · 23 January · Evening Shift · Chemistry · Chemical Kinetics

Given above is the concentration vs time plot for a dissociation...

Given above is the concentration vs time plot for a dissociation reaction :

\mathrm{A} \rightarrow \mathrm{nB}

. Based on the data of the initial phase of the reaction (initial 10 min), the value of n is

\_\_\_\_

Options

Correct answer

A. 3

Step-by-step solution

A \rightarrow nB

t = 0

[A] = 0.05

[B] = 0

t = 10

min:

[A] = 0.04

[B] = 0.01 \times n

From the graph,

[B]

t = 10

min

= 0.03

0.01 \times n = 0.03

n = 3

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