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JEE Main20254 Apr 2025Morning ShiftChemistryChemical KineticsActual

Rate law for a reaction between A and B is given by R = k [ ~A ]^ n [ ~B ]^ m If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction ( r₂ r₁ ) is

Options

  1. A2^ (n-m)
  2. B(n-m)
  3. C(m+n)
  4. D1 2^ m+n

Correct answer

A. 2^ (n-m)

Step-by-step solution

r ₁= k [ ~A ]^ n [ ~B ]^ m Now A is doubled & B is halved in concentration r ₂= k 2^ n [ ~A ]^ n [ ~B ]^ m 2^ m Now r₂ r₁ =2^ (n-m)

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