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JEE Main 20248 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2024 · 8 April · Evening Shift · Chemistry · Chemical Kinetics

For a reaction (A K_1 ~B K_2 C) If the rate of formation of B is...

For a reaction (\mathrm{A} \xrightarrow{\mathrm{K}_1} \mathrm{~B} \xrightarrow{\mathrm{K}_2} \mathrm{C}) If the rate of formation of BB is set to be zero then the concentration of BB is given by :

Options

  1. A(\left(\mathrm{K}_1+\mathrm{K}_2\right)[\mathrm{A}])
  2. B(\left(\mathrm{K}_1 / \mathrm{K}_2\right)[\mathrm{A}])
  3. C(\left(\mathrm{K}_1-\mathrm{K}_2\right)[\mathrm{A}])
  4. D(\mathrm{K}_1 \mathrm{~K}_2[\mathrm{~A}])

Correct answer

B. (\left(\mathrm{K}_1 / \mathrm{K}_2\right)[\mathrm{A}])

Step-by-step solution

Rate of formation of BB is d[B]dt=k1[ A]−k2[ B]0=k1[ A]−k2[ B](k1k2)[A]=[B]\begin{aligned} & \frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}}=\mathrm{k}_1[\mathrm{~A}]-\mathrm{k}_2[\mathrm{~B}] \\ & 0=\mathrm{k}_1[\mathrm{~A}]-\mathrm{k}_2[\mathrm{~B}] \\ & \left(\frac{\mathrm{k}_1}{\mathrm{k}_2}\right)[\mathrm{A}]=[\mathrm{B}]\end{aligned}
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