JEE Main 2024 6 April Morning Shift
Exam JEE Main
Year 2024
Date 6 April
Shift Morning Shift
Subject Chemistry
Chapter Chemical Kinetics JEE Main 2024 · 6 April · Morning Shift · Chemistry · Chemical Kinetics
Time required for (99.9 \%) completion of a first order reaction is...
Time required for (99.9 \%) completion of a first order reaction is _______ times the time required for completion of (90 \%) reaction.(nearest integer)
Step-by-step solution
K = 1 t 99.9 % ln ( 100 0.1 ) = 1 t 90 % ln ( 100 10 ) t 99.9 % = t 90 % ℓ n ( 1 0 3 ) ℓ n 10 t 99.9 % = t 90 % × 3 \begin{aligned} & \mathrm{K}=\frac{1}{\mathrm{t}_{99.9 \%}} \ln \left(\frac{100}{0.1}\right)=\frac{1}{\mathrm{t}_{90 \%}} \ln \left(\frac{100}{10}\right) \\ & \mathrm{t}_{99.9 \%}=\mathrm{t}_{90 \%} \frac{\ell \mathrm{n}\left(10^3\right)}{\ell \mathrm{n} 10} \\ & \mathrm{t}_{99.9 \%}=\mathrm{t}_{90 \%} \times 3\end{aligned} K = t 99.9% 1 ln ( 0.1 100 ) = t 90% 1 ln ( 10 100 ) t 99.9% = t 90% ℓ n 10 ℓ n ( 1 0 3 ) t 99.9% = t 90% × 3
Practice Chemical Kinetics on Quantrex Academy →
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