Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 20245 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
5 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2024 · 5 April · Morning Shift · Chemistry · Chemical Kinetics

During Kinetic study of reaction (2 A+B arrow C+D), the following...

During Kinetic study of reaction (2 A+B \rightarrow C+D), the following results were obtained : ( A [M]  B [M]  initial rate of formation of D  I 0.10.16.0×10−3 II 0.30.27.20×10−2 III 0.30.42.88×10−1 IV 0.40.12.40×10−2\begin{array}{llll} & \text{ A [M] } & \text{ B [M] } & \text{ initial rate of formation of D } \\ \text{ I } & 0.1 & 0.1 & 6.0 \times 10^{-3} \\ \text{ II } & 0.3 & 0.2 & 7.20 \times 10^{-2} \\ \text{ III } & 0.3 & 0.4 & 2.88 \times 10^{-1} \\ \text{ IV } & 0.4 & 0.1 & 2.40 \times 10^{-2} \\ \end{array}) Based on above data, overall order of the reaction is ______

Correct answer

0

Step-by-step solution

r=K[A]x[B]y(I)6×10−3=K[0.1]x[0.1]y(IV)2.4×10−2=K[0.4]x[0.1]y(IV)/(I)4=(4)xx=1r=K[A]x[B]y\begin{aligned} & \mathrm{r}=\mathrm{K}[\mathrm{A}]^{\mathrm{x}}[\mathrm{B}]^{\mathrm{y}} \\ & (\mathrm{I}) 6 \times 10^{-3}=\mathrm{K}[0.1]^{\mathrm{x}}[0.1]^{\mathrm{y}} \\ & (\mathrm{IV}) 2.4 \times 10^{-2}=\mathrm{K}[0.4]^{\mathrm{x}}[0.1]^{\mathrm{y}} \\ & \quad(\mathrm{IV}) /(\mathrm{I}) \\ & 4=(4)^{\mathrm{x}} \\ & \quad \mathrm{x}=1 \\ & \mathrm{r}=\mathrm{K}[\mathrm{A}]^{\mathrm{x}}[\mathrm{B}]^{\mathrm{y}}\end{aligned} (III) 2.88×10−1=K[0.3]x[0.4]y (II) 7.2×10−2=K[0.3]x[0.2]y (III)/(II) \begin{aligned} & \text{ (III) } 2.88 \times 10^{-1}=\mathrm{K}[0.3]^{\mathrm{x}}[0.4]^{\mathrm{y}} \\ & \text{ (II) } 7.2 \times 10^{-2}=\mathrm{K}[0.3]^{\mathrm{x}}[0.2]^{\mathrm{y}} \\ & \text{ (III)/(II) }\end{aligned} 4=2yy=2\begin{aligned} & 4=2^y \\ & y=2\end{aligned}OverallorderOverall order=x+y=1+2=3$
Practice Chemical Kinetics on Quantrex Academy →

More from Chemical Kinetics

For a reversible reaction R leftharpoons P , at constant temperature, both the forward… JEE Advanced 2026For a first-order reaction R P at a given temperature, k is the rate constant. For this… JEE Advanced 2026Given below are two statements: R=8.314 J K ^ -1 mol ^ -1 and 1 cal =4.2 J Statement I… JEE Main 2026Decomposition of a hydrocarbon follows the equation k = (5.5 × 10^ 11 \,s^ -1 )\,e^… JEE Main 2026For a reaction A arrow P at T K , the half life (t_ 1/2 ) is plotted as a function of… JEE Main 2026First order gas phase reaction A arrow B + C p_i = initial pressure of gas A, p_t = total… JEE Main 2026If the half life of a first order reaction is 6.93 minutes then the time required for… JEE Main 2026Consider the given graph showing variation of reactant concentration with time. Three… JEE Main 2026 Full Chemical Kinetics list All JEE Main PYQs