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JEE Main 20241 FebruaryEvening Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2024 · 1 February · Evening Shift · Chemistry · Chemical Kinetics

The following data were obtained during the first order thermal...

The following data were obtained during the first order thermal decomposition of a gas AA at constant volume:

A(g)→2B(g)+C(g)A\left(g\right) \to 2B\left(g\right) + C\left(g\right)

S. No                 Time/s                 Total pressure/(atm)

1.1 .                     00                     0.10 . 1

 2.2 .                      115115                     0.280 . 28

The rate constant of the reaction is _______ ×10−2s−1\times {10}^{- 2}{s}^{- 1} (nearest integer)

Correct answer

0

Step-by-step solution

t=0t=115sec.\begin{array}{ll}t = 0 \\ t = 115sec .\end{array}A(g)0.10.1−x\begin{array}{ll}A\left(g\right) \\ 0 . 1 \\ 0 . 1 - x\end{array}→\begin{array}{ll}\to\end{array}2B(g)2x\begin{array}{ll}2B\left(g\right) \\ 2x\end{array}+\begin{array}{ll}+\end{array}C(g)2x\begin{array}{ll}C\left(g\right) \\ 2x\end{array}</p><p></p><p>0 . 1 + 2x = 0 . 28</p><p></p><p>2x = 0 . 18</p><p></p><p>x = 0 . 09</p><p></p><p>K = \dfrac{1}{115}ln\dfrac{0 . 1}{0 . 1 - 0 . 09}</p><p></p><p>= 0 . 0200\sec^{- 1}</p><p></p><p>= 2 \times {10}^{- 2}\sec^{- 1}$

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