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NO 2 required for a reaction is produced by decomposition of N 2 O 5 in CCl 4 as by equation 2 N 2 O 5 ( g ) → 4 NO 2 ( g ) + O 2 ( g ) The initial concentration of N 2 O 5 is 3 mol L - 1 and it is 2 . 75 mol L - 1 after 30 minutes. The rate of formation of NO 2 is x × 10 - 3 mol L - 1 min - 1 , value of x is ________.

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Step-by-step solution

The given reaction is, 2 N 2 O 5 ( g ) → 4 NO 2 ( g ) + O 2 ( g ) The initial concentration of N 2 O 5 is 3 mol L - 1 and it is 2 . 75 mol L - 1 after 30 minutes. Now, - Δ N 2 O 5 Δt = - ( 2 . 75 - 3 ) 30 - 0 mol L - 1 min - 1 = 0 . 25 30 1 2 × Δ N 2 O 5 Δt = 1 4 - Δ NO 2 Δt - Δ NO 2 Δt = 0 . 25 30 × 2 = 1 . 66 × 10 - 2 M / Min ≃ 17 × 10 - 3 M / Min

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