A first order reaction has the rate constant, k = 4 . 6 × 10 - 3 s - 1 . The number of correct statement/s from the following is/are Given: log 3 = 0 . 48 . A. Reaction completes in 1000 s . B. The reaction has a half-life of 500 s . C. The time required for 10 % completion is 25 times the time required for 90% completion. D. The degree of dissociation is equal to 1 - e - kt . E. The rate and the rate constant h

Step-by-step solution

For a first order reaction: t 1 2   =   0 . 693 k   =   0 . 693 4 . 6 × 10 - 3   s - 1   =   150 . 65   s For a first order reaction, t 10 % = 1 K ln a a - x = 1 K ln 100 90 t 10 % = 2 . 303   K ( log   10 - log   9 ) t 10 % = 2 . 093   K × ( 0 . 04 ) Similarly t 90 % = 1   K ln 100 10 t 90 % = 2 . 303   K t 90 % t 10 % = 1 0 . 04 = 25 We know, e kt = a a - x a - x a = e - kt x = a 1 - e - kt α = x a = 1 - e - kt Thus, only option