The equation k = (6 . 5 × 10 ^ 12 s ^ - 1 ) e ^ - 26000K / T is...

The equation $k = \left(6 . 5 \times {10}^{12}{s}^{- 1}\right){e}^{- 26000K / T}$ is followed for the decomposition of compound $A$ . The activation energy for the reaction is ____ $KJ{mol}^{- 1}$ . [nearest integer]

(Given: $R = 8 . 314J{K}^{- 1}{mol}^{- 1}$ )

Correct answer

Step-by-step solution

$K = {Ae}^{- {E}_{a} / RT} = \left(6 . 5 \times {10}^{12}{s}^{- 1}\right){e}^{- 26000K / T}$

$\dfrac{Ea}{8 . 314} = 26000$

$Ea = 216 . 164kJ / mol$ .

Hence,the activation energy of the given reaction is $216KJ{mol}^{- 1}$

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