The rate constant for a first order reaction is given by the following equation :
$lnk = 33 . 24 - \dfrac{2 . 0 \times {10}^{4}K}{T}$
The Activation energy for the reaction is given by ${kJmol}^{- 1}$ . (In Nearest integer) (Given : $R = 8 . 3J{K}^{- 1}{mol}^{- 1}$ )

Question

The rate constant for a first order reaction is given by the following equation :

$lnk = 33 . 24 - \dfrac{2 . 0 \times {10}^{4}K}{T}$

The Activation energy for the reaction is given by ${kJmol}^{- 1}$ . (In Nearest integer) (Given : $R = 8 . 3J{K}^{- 1}{mol}^{- 1}$ )

Quantrex Academy · Accepted Answer

Correct answer: 0

lnk = lnA - E _ A RT Given: lnk = 33 . 24 - 2 . 0 × 10 ^ 4 T ∴ on comparing E _ A R = 2 . 0 × 10 ^ 4 ∴ E _ A = 2 . 0 × 10 ^ 4 × R ⇒ E _ A = 2 . 0 × 10 ^ 4 × 8 . 3J ⇒ E _ A = 16 . 6 × 10 ^ 4 J = 166kJ

The rate constant for a first order reaction is given by the...

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