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JEE Main202122 Jul 2021Morning ShiftChemistryChemical KineticsActual

N 2 O 5 ( g ) → 2 NO 2 ( g ) + 1 2 O 2 ( g ) In the above first order reaction the initial concentration of N 2 O 5 is 2 . 40 × 10 - 2 mol L - 1 at 318 K . The concentration of N 2 O 5 after 1 hour was 1 . 60 × 10 - 2 mol L - 1 . The rate constant of the reaction at 318 K is × 10 - 3 min - 1 (Nearest integer): [ Given : log 3 = 0 . 477 , log 5 = 0 . 699 ]

Correct answer

0

Step-by-step solution

K = 2 . 303 t log N 2 O 5 0   N 2 O 5 1 = 2 . 303 60 log 2 . 4 1 . 6 = 6 . 76 × 10 - 3   min - 1 ≈ 7 × 10 - 3   min - 1

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