JEE Main202118 Mar 2021Morning ShiftChemistryChemical KineticsActual
2 NO ( g ) + Cl 2 ( g ) ⇌ 2 NOCl ( s ) This reaction was studied at - 10 ° C and the following data was obtained run [ NO ] 0 Cl 2 0     r 0 1 0.10 0.10 0.18 2 0.10 0.20 0.35 3 0.20 0.20 1.40 [ NO ] 0 and Cl 2 0 are the initial concentrations and r 0 is the initial reaction rate. The overall order of the reaction is (Round off to the Nearest Integer).
Correct answer
0
Step-by-step solution
r = k [ NO ] m Cl 2 n = k ( 0.1 ) m ( 0.1 ) n . . . 1 = k ( 0.1 ) m ( 0.2 ) n … . ( 2 ) = k ( 0.2 ) m ( 0.2 ) n … . ( 3 ) n = 1 m = 2 m + n = 3