JEE Main202116 Mar 2021Morning ShiftChemistryChemical KineticsActual
The decomposition of formic acid on gold surface follows first order kinetics. If the rate constant at 300   K is 1 . 0 × 10 - 3   s - 1 and the activation energy E a = 11 . 488   kJ   mol - 1 , the rate constant at 200   K is _________ × 10 - 5   s - 1 . (Round of to the Nearest Integer). (Given R = 8 . 314   J   mol - 1   K - 1 )
Correct answer
0
Step-by-step solution
K 300 = 10 - 3      K 200 = ? E a = 11 . 488 KJ / mole    R = 8 . 314   J / mole - K so ℓ n K 300   K 200 = E a R 1 200 - 1 300 ℓ n K 300   K 200 = 11 . 488 × 1000 × 100 8 . 314 × 200 × 300 = 2 . 303 = ℓ n 10 so K 300   K 200 = 10 K 200 = 1 10 × K 300 = 10 - 4 = 10 × 10 - 5   sec - 1