JEE Main202125 Feb 2021Evening ShiftChemistryChemical KineticsActual
The rate constant of a reaction increases by five times on increase in temperature from 27 ° C to 52 ° C . The value of activation energy in kJmol - 1 is ___ .(Rounded-off to the nearest integer) R = 8 . 314 J K - 1 mol - 1
Correct answer
0
Step-by-step solution
T 1 = 300   K ,   T 2 = 325   K ,   K 2 = 5   K ln K 2   K 1 = Ea R 1   T 1 - 1   T 2 or, ln 5 = Ea 8 . 314 1 300 - 1 325 or, Ea = 0 . 7 × 2 . 303 × 8 . 314 × 12 × 325 = 52271   J = 52 . 271   kJ Nearest integer answer will be 52   kJ