The rate constant of a reaction increases by five times on increase...

${T}_{1} = 300K, {T}_{2} = 325K, {K}_{2} = 5K$

$ln\dfrac{{K}_{2}}{{K}_{1}} = \dfrac{Ea}{R}\left[\dfrac{1}{{T}_{1}} - \dfrac{1}{{T}_{2}}\right]$

or, $\ln 5 = \dfrac{Ea}{8 . 314}\left[\dfrac{1}{300} - \dfrac{1}{325}\right]$

or, $Ea = 0 . 7 \times 2 . 303 \times 8 . 314 \times 12 \times 325$

$= 52271J = 52 . 271kJ$

Nearest integer answer will be $52kJ$