Sucrose hydrolyses in acid solution into glucose and fructose...

${C}_{12}{H}_{22}{O}_{11} + {H}_{2}O\mathop{\to}_{{t}_{1/2} = \dfrac{10}{3}hr}^{order}\mathop{{C}_{6}{H}_{12}{O}_{6}}_{Glucose} + \mathop{{C}_{6}{H}_{12}{O}_{6}}_{Fructose}$

$t = 0a = {\left[A\right]}_{0}$

$t = 9hra - x = {\left[A\right]}_{t}$

from I order kinetic: $\dfrac{k \times t}{2 . 303} = log\dfrac{{\left|A\right|}_{0}}{{\left|A\right|}_{t}}$

$⇒ \dfrac{\ln 2 \times 9}{\dfrac{10}{3} \times 2 . 303} = \log \left(\dfrac{1}{f}\right)$

$⇒ \dfrac{0 . 693 \times 9 \times 3}{23 . 03} = \log \left(\dfrac{1}{f}\right)$

$⇒ \log \left(\dfrac{1}{f}\right) = 0 . 81246 = 81 . 24 \times {10}^{- 2}$

$⇒ x = 81$