The results given in the below table were obtained during kinetic...

Rate $= k [ A{]}^{a} [ B{]}^{b}$
from Exp \left(1\right) \text{$and$} \left(2\right)b = 2$<br />from Exp \left(1\right) \text{\text{ and } } \left(3\right)a = 1$
from$Exp \left(2\right) \text{\text{ and } } \left(4\right) ⇒ 3 = {\left(\dfrac{x}{0 . 1}\right)}^{1}$ so $x = 0 . 3$

from $Exp \left(1\right) \text{\text{ and } } \left(5\right) ⇒ 48 = {\left(3\right)}^{1}{\left(\dfrac{y}{0 . 1}\right)}^{2}$
${\left(4\right)}^{2} = {\left(\dfrac{y}{0 . 1}\right)}^{2}\text{so}y = 0 . 4$