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JEE Main201912 Apr 2019Morning ShiftChemistryChemical KineticsActual

In the following reaction; x A → y B log 10 ⁡ - d A d t = log 10 ⁡ - d B d t + 0.3010 ‘A’ and ‘B’ respectively can be:

Options

  1. AC 2 H 4 and C 4 H 8
  2. BC 2 H 2 and C 6 H 6
  3. Cn-Butane and Iso-butane
  4. DN 2 O 4 and N O 2

Correct answer

A. C 2 H 4 and C 4 H 8

Step-by-step solution

From the rate law: log - d A d t = l o g d B d t + 0.3010 = log ⁡ - d A d t = log ⁡ d B d t + log ⁡ 2 - d A d t = 2 × d B d t 2 A → B and we know 2 C 2 H 4 → C 4 H 8

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