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JEE Main 201910 JanuaryMorning Shift
Exam
JEE Main
Year
2019
Date
10 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2019 · 10 January · Morning Shift · Chemistry · Chemical Kinetics

Consider the given plots for a reaction obeying Arrhenius equation...

Consider the given plots for a reaction obeying Arrhenius equation (0°C<T<300°C):( 0 ° C < T < 300 ° C ) : (KKand Ea{E}_{a} are rate constant and activetion energy, respectively )

(I) Consider the given plots for a reaction obeying Arrhenius equation ( 0 ° C (I) (II)

(II) Consider the given plots for a reaction obeying Arrhenius equation ( 0 ° C (I) (II)

Options

  1. AI is wrong but II is right
  2. BBoth I and II are wrong
  3. CI is right but II is wrong
  4. DBoth I and II are correct

Correct answer

D. Both I and II are correct

Step-by-step solution

K=Ae−Ea/RTK = A{e}^{- {E}_{a} / RT}

KK decreases exponentially with Ea{E}_{a}

∴∴ The first graph is correct.

But temperature is given in oC{}^{o}C
So, K≠0K \ne 0 at 0oC{0}^{o}C.

∴∴ For temperature between 0oC{0}^{o}Cand 300oC,{300}^{o}C, the graph will come like (II)
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