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JEE Main 20179 AprilOnline
Exam
JEE Main
Year
2017
Date
9 April
Mode
Online
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2017 · 9 April · Online · Chemistry · Chemical Kinetics

The rate of a reaction quadruples when the temperature changes from...

The rate of a reaction quadruples when the temperature changes from 300300 to 310K310K . The activation energy of this reaction is:

(Assume Activation energy and pre-exponential factor are independent of temperature; ln⁡(2)=0.693;R=8.314Jmol−1K−1\ln ( 2 ) = 0 . 693; R = 8 . 314J{mol}^{- 1}{K}^{- 1})

Options

  1. A53.6kJmol−153 . 6kJ{mol}^{- 1}
  2. B214.4kJmol−1214 . 4kJ{mol}^{- 1}
  3. C107.2kJmol−1107 . 2kJ{mol}^{- 1}
  4. D53.7kJmol−153 . 7kJ{mol}^{- 1}

Correct answer

C. 107.2kJmol−1107 . 2kJ{mol}^{- 1}

Step-by-step solution

The activation energy, rate constant and temperature can be related using Arrhenius equation.

k=Ae−EaRTk = {Ae}^{- \dfrac{{E}_{a}}{RT}}

ln⁡(k2k1)=EaR(1T1−1T2)\ln \left(\dfrac{{k}_{2}}{{k}_{1}}\right) = \dfrac{{E}_{a}}{R}\left(\dfrac{1}{{T}_{1}} - \dfrac{1}{{T}_{2}}\right)

ln⁡(4)=EaR(1300−1310)\ln \left(4\right) = \dfrac{{E}_{a}}{R}\left(\dfrac{1}{300} - \dfrac{1}{310}\right)

2×0.693=EaR(10300×310)2 \times 0 . 693 = \dfrac{{E}_{a}}{R}\left(\dfrac{10}{300 \times 310}\right)

Ea=2×0.693×300×310×8.31410=107.2kJ/mol{\text{E}}_{\text{a}} = \dfrac{2 \times 0.693 \times 300 \times 310 \times 8.314}{10} = 107.2\text{kJ/mol}

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