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JEE Main2015ChemistryChemical KineticsActual

For the equilibrium, A g ⇌ B g , ∆ H is - 40 kJ / mol . If the ratio of the activation energies of the forward E f and reverse E b reactions is 2 3 then:

Options

  1. AE f = 30   kJ / mol , E b = 70   kJ / mol
  2. BE f = 70   kJ / mol , E b = 30   kJ / mol
  3. CE f = 80   kJ / mol , E b = 120   kJ / mol
  4. DE f = 60   kJ / mol , E b = 100   kJ / mol

Correct answer

C. E f = 80   kJ / mol , E b = 120   kJ / mol

Step-by-step solution

Activation energy is the minimum amount of energy that must be provided for compounds to result in a chemical reaction. A g ⇌ B g   ;   ∆ H = - 40 kJ/mole ∆ H = E a f - E a b = - 40   k J E a f E a b = 2 3 ⇒   E a f = 2 3 E a b ⇒ 2 3   E a b - E a b = - E a b 3 = - 40   k J E a b = + 120   k J E a f = 2 3 × 120 = 80   k J

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