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JEE Main2014ChemistryChemical KineticsActual

For the reaction, 3A + 2B → C + D , the differential rate law can be written as :

Options

  1. A+ 1 3 d A dt = - d C dt = k A n B m
  2. B1 3 d A dt = d C dt = k A n B m
  3. C- 1 3 d A dt = d C dt = k A n B m
  4. D- d A dt = d C dt = k A n B m

Correct answer

C. - 1 3 d A dt = d C dt = k A n B m

Step-by-step solution

- 1 3 d A dt = - 1 2 d B dt = + d C dt = d D dt = k A n B m is the rate law

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