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JEE Main2007ChemistryChemical KineticsActual

The energies of activation for forward and reverse reactions for A₂+B₂ 2 A B are 180 ~kJ ~mol ⁻¹ and 200 ~kJ ~mol ⁻¹ respectively. The presence of catalyst lowers the activation energy of both (forward and reverse) reactions by 100 ~kJ ~mol ⁻¹ . The enthalpy change of the reaction ( A ₂+ B ₂ 2 AB ) in the presence of catalyst will be (in kJ ~mol ⁻¹ )

Options

  1. A300
  2. B120
  3. C280
  4. D20

Correct answer

D. 20

Step-by-step solution

So, H_ Reaction =E_f-E_b=80-100=-20 Hence, (D) is correct.

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