JEE Main2007ChemistryChemical KineticsActual
The energies of activation for forward and reverse reactions for A₂+B₂ 2 A B are 180 ~kJ ~mol ⁻¹ and 200 ~kJ ~mol ⁻¹ respectively. The presence of catalyst lowers the activation energy of both (forward and reverse) reactions by 100 ~kJ ~mol ⁻¹ . The enthalpy change of the reaction ( A ₂+ B ₂ 2 AB ) in the presence of catalyst will be (in kJ ~mol ⁻¹ )
Options
- A300
- B120
- C280
- D20
Correct answer
D. 20
Step-by-step solution
So, H_ Reaction =E_f-E_b=80-100=-20 Hence, (D) is correct.