JEE Main 20249 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 9 April
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- d and f Block Elements
JEE Main 2024 · 9 April · Morning Shift · Chemistry · d and f Block Elements
(0.05 M CuSO_4) when treated with (0.01 M K_2 Cr_2 O_7) gives green...
(0.05 \mathrm{M} \mathrm{CuSO}_4) when treated with (0.01 \mathrm{M} \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7) gives green colour solution of (\mathrm{Cu}_2 \mathrm{Cr}_2 \mathrm{O}_7). The two solutions are separated as shown below :
[SPM : Semi Permeable Membrane]

Due to osmosis :
Due to osmosis :
Options
- AMolarity of (\mathrm{CuSO}_4) solution is lowered.
- BMolarity of (\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7) solution is lowered.
- CGreen colour formation observed on side Y.
- DGreen colour formation observed on side X.
Correct answer
A. Molarity of (\mathrm{CuSO}_4) solution is lowered.
Step-by-step solution
Only solvent Molecules are allowed to pass through the SPM.
