The correct order of basicity of oxides of vanadium is

Step-by-step solution

V 2 O 3 : In, V 2 O 3 , the oxidation state of V is as follows 2 ( x )   +   3 ( - 2 )   =   0 ⇒   2 x   -   6   =   0 ⇒   x   =   6 2   =   3 The oxidation state of V in V 2 O 3 is +3. The vanadium is present in its lowest oxidation state. The vanadium tends to donate the pair of electrons. Hence, it is basic oxide. V 2 O 5 : In V 2 O 5 , the oxidation state of V is as follows 2 ( x )   +   5 ( - 2 )   =   0 &#865