Match the List-I with List-II : Cations Group reaction P → Pb ^ 2 + , Cu ^ 2 + H _ 2 S gas in presence of dilute HCl Q → Al ^ 3 + , Fe ^ 3 + ( NH _ 4 ) _ 2 CO _ 3 in presence of NH _ 4 OH R → Co ^ 2 + , Ni ^ 2 + NH _ 4

Question

Quantrex Academy · Accepted Answer

Correct answer: D. P → i, Q → iii, R → iv, S → ii

Group reagents for precipitating ions:

Group	Cations	Group reagent
Zero	${NH}_{4}^{+}$	None
I	${Pb}^{2 +}$	Dilute HCl
II	${Pb}^{2 +}, {Cu}^{2 +}, {As}^{3 +}$	${H}_{2}S$ gas in presence of dil. HCl
III	${Al}^{3 +}, {Fe}^{3 +}$	${NH}_{4}OH$ in presence of ${NH}_{4}Cl$
IV	${Co}^{2 +}, {Ni}^{2 +}, {Mn}^{2 +}, {Zn}^{2 +}$	${H}_{2}S$ in presence of ${NH}_{4}OH$
V	${Ba}^{2 +}, {Sr}^{2 +}, {Ca}^{2 +}$	$( {NH}_{4}{)}_{2}{CO}_{3}$ in presence of ${NH}_{4}OH$
VI	${Mg}^{2 +}$	None

So, the correct answer is $P \to i, Q \to iii, R \to iv, S \to ii$

Cations	Group reaction
$P \to {Pb}^{2 +}, {Cu}^{2 +}$	${H}_{2}S$ gas in presence of dilute $HCl$
$Q \to {Al}^{3 +}, {Fe}^{3 +}$	${\left({\text{ NH }}_{4}\right)}$ _{2}{CO}_{3} $in presence of$ {NH}_{4}OH $</td> </tr> <tr> <td>$ R \to {Co}^{2 +}, {Ni}^{2 +} $</td> <td>$ {NH}_{4}OH $in presence of$ {NH}_{4}CI $</td> </tr> <tr> <td>$ S \to {Ba}^{2 +}, {Ca}^{2 +} $</td> <td>$ {H}_{2}S $in presence of$ {NH}_{4}OH

Match the List-I with List-II : Cations Group reaction P → Pb ^ 2 +...

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