The magnetic moment of a transition metal compound has been calculated to be 3 . 87 BM . The metal ion is

Step-by-step solution

The magnetic moment, μ s ​ = n ( n + 2 ) ​ BM where n is the number of unpaired electrons. Cr + 2   :   Ar ,   3 d 4 ,   4 s °   n = 4 ,   μ = 4 ( 4 + 2 ) = 24 = 4 . 89   BM Mn + 2   :   Ar ,   3 d 5 ,   4 s °   n = 5 ,   μ = 5 ( 5 + 2 ) = 35 = 5 . 91   BM V + 2   :   Ar ,   3 d 3 ,   4 s °   n = 3 ,   μ = 3 ( 3 + 2 ) = 15 = 3 . 87   BM Ti + 2   :   Ar , &