The metal ion (in gaseous state) with lowest spin-only magnetic moment value is

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Quantrex Academy · Accepted Answer

Correct answer: B. Ni ^ 2 +

Ion Electronic configuration No. of unpaired electron 1 Cr ^ 2 + 3 d ^ 4 4 2 V ^ 2 + 3 d ^ 3 3 3 Fe ^ 2 + 3 d ^ 6 4 4 Ni ^ 2 + 3 d ^ 8 2 Magnetic moment(spin only) is calculated by the formula μ = n ( n + 2 ) BM . Magnetic moment (spin only)is directly proportional to the number of unpaired electrons. Hence, less is the number of unpaired electrons less is the magnetic moment (spin only). As Ni 2+ has the least number of unpaired electrons it has the least magnetic moment (spin only) among the given options.

	Ion	Electronic configuration	No. of unpaired electron
1	${Cr}^{2 +}$	$3{d}^{4}$	$4$
2	${V}^{2 +}$	$3{d}^{3}$	$3$
3	${Fe}^{2 +}$	$3{d}^{6}$	$4$
4	${Ni}^{2 +}$	$3{d}^{8}$	$2$

The metal ion (in gaseous state) with lowest spin-only magnetic...

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