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JEE Main 202225 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Morning Shift
Subject
Chemistry
Chapter
d and f Block Elements

JEE Main 2022 · 25 June · Morning Shift · Chemistry · d and f Block Elements

Among the following, which is the strongest oxidizing agent?

Among the following, which is the strongest oxidizing agent?

Options

  1. AMn3+{Mn}^{3 +}
  2. BTi3+{Ti}^{3 +}
  3. CFe3+{Fe}^{3 +}
  4. DCr3+{Cr}^{3 +}

Correct answer

A. Mn3+{Mn}^{3 +}

Step-by-step solution

The substance which will have the highest value of reduction potential will be the strongest oxidising agent. The values of reduction potential are as follow

EMn3+/Mn2+0=+1.57VETi3+/Ti2+0=−0.37VEFe3+/Fe2+0=+0.77VECr3+/Cr2+0=−0.41V\begin{array}{ll}{E}_{{Mn}^{3 +} / {Mn}^{2 +}}^{0} = + 1 .57 V \\ {E}_{{Ti}^{3 +} / {Ti}^{2 +}}^{0} = - 0 .37 V \\ {E}_{{Fe}^{3 +} / {Fe}^{2 +}}^{0} = + 0 .77 V \\ {E}_{{Cr}^{3 +} / {Cr}^{2 +}}^{0} = - 0 .41 V\end{array}

As we can see Mn+3{Mn}^{+ 3} has the highest value of standard reduction potential, so it will be the strongest oxidising agent.

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