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JEE Main202125 Jul 2021Evening ShiftChemistryd and f Block ElementsActual

Number of electrons present in 4 f orbital of Ho 3 + ion is ________ (Given Atomic No. of Ho =67)

Correct answer

0

Step-by-step solution

Ho = [ Xe ] 4 f 11 6   s 2 Ho 3 + = [ Xe ] 4 f 10 so number of e - present in 4 f is 10   .

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