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JEE Main 20206 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Morning Shift
Subject
Chemistry
Chapter
d and f Block Elements

JEE Main 2020 · 6 September · Morning Shift · Chemistry · d and f Block Elements

The lanthanoid that does NOT show + 4 oxidation state is:

The lanthanoid that does NOT show + 4 oxidation state is:

Options

  1. ADy
  2. BCe
  3. CEu
  4. DTb

Correct answer

C. Eu

Step-by-step solution

Eu(z=63)=4F76s2Eu ( z = 63 ) = 4{F}^{7}6{s}^{2}
Dy(z=66)=4F106s2Dy ( z = 66 ) = 4{F}^{10}6{s}^{2}
Tb(z=65)=4F96s2Tb ( z = 65 ) = 4{F}^{9}6{s}^{2}
Ce(58)=4F15d16s2Ce ( 58 ) = 4{F}^{1}5{d}^{1}6{s}^{2}
Dy,TbDy, Tb and CeCe show +4+ 4 oxidation state while EuEu do not show +4+ 4oxidation state.
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