Consider the hydrated ions of T i ^ 2 + , V ^ 2 + , T i ^ 3 + and S...

Consider the hydrated ions of

T{i}^{2 +}, {V}^{2 +}, T{i}^{3 +}

and

S{c}^{3 +}

. The correct order of their spin-only magnetic moments is: Consider the hydrated ions of T i ^ 2 + , V ^ 2 + , T i ^ 3 + and S c ^ 3 + . The correct order of their spin-only

Options

A $S{c}^{3 +} < T{i}^{3 +} < {V}^{2 +} < T{i}^{2 +}$
B $T{i}^{3 +} < T{i}^{2 +} < S{c}^{3 +} < {V}^{2 +}$
C $S{c}^{3 +} < T{i}^{3 +} < T{i}^{2 +} < {V}^{2 +}$
D ${V}^{2 +} < T{i}^{2 +} < T{i}^{3 +} < S{c}^{3 +}$

Correct answer

C. $S{c}^{3 +} < T{i}^{3 +} < T{i}^{2 +} < {V}^{2 +}$

Step-by-step solution

Magnetic moment

\left(\mu\right) = \sqrt{n\left(n + 2\right)}

More than value of n, more will be magnetic moment.

T{i}^{+ 2}

electronic configuration;

3{d}^{2}

\mu = \sqrt{2\left(2 + 2\right)} = 2.82

{\text{Ti}}^{+ 3} ⇒ 3{d}^{1}

\mu = \sqrt{1\left(1 + 2\right)} = \sqrt{3} = 1.73

{V}^{+ 2} ⇒ 3{d}^{3}

\mu = \sqrt{3\left(3 + 2\right)} = 3.87

S{c}^{3 +} ⇒ \left[Ar\right]

no unpaired electron.

\to \mu = 0

Hence Order of Magnetic Moment is

{V}^{+ 2} > T{i}^{+ 2} > T{i}^{+ 3} > S{c}^{+ 3}

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