JEE Main2013Chemistryd and f Block ElementsActual
Given E Cr 3 + / Cr o = - 0 . 74 V; E MnO 4 - / Mn 2 + o = 1 . 51 V E Cr 2 O 7 2 - / Cr 3 + o = 1 . 33 V; E Cl 2 | Cl - o = 1 . 36 V Based on the data given above, strongest oxidising agent will be:
Options
- AMn 2 +
- BMnO 4 -
- CCl -
- DCr 3 +
Correct answer
B. MnO 4 -
Step-by-step solution
Strongest oxidising agent has the highest tendency to get reduce therefore will have the highest standard reduction potential. So among the given oxidising agents the species have highest value of reduction potential is: E MnO 4 - / Mn 2 + o = 1 . 51 V