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What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

Options

  1. ACr ₂ O ₇²⁻ and H ₂ O are formed
  2. BCrO ²⁻ ₄ is reduced to +3 state of Cr
  3. CCrO ₄²⁻ is oxidized to +7 state of Cr
  4. DCr ³⁺ and Cr ₂ O ²⁻ ₇ are formed

Correct answer

A. Cr ₂ O ₇²⁻ and H ₂ O are formed

Step-by-step solution

Cr ₂ O ₇²⁻+ OH ⁻ 2 CrO ₄²⁻+ H ⁺ . The above equilibrium shifts to L.H.S. on addition of acid.

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